(2x+5)(5x^2-27x+28)=0

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Solution for (2x+5)(5x^2-27x+28)=0 equation: 


Simplifying
(2x + 5)(5x2 + -27x + 28) = 0

Reorder the terms:
(5 + 2x)(5x2 + -27x + 28) = 0

Reorder the terms:
(5 + 2x)(28 + -27x + 5x2) = 0

Multiply (5 + 2x) * (28 + -27x + 5x2)
(5(28 + -27x + 5x2) + 2x * (28 + -27x + 5x2)) = 0
((28 * 5 + -27x * 5 + 5x2 * 5) + 2x * (28 + -27x + 5x2)) = 0
((140 + -135x + 25x2) + 2x * (28 + -27x + 5x2)) = 0
(140 + -135x + 25x2 + (28 * 2x + -27x * 2x + 5x2 * 2x)) = 0
(140 + -135x + 25x2 + (56x + -54x2 + 10x3)) = 0

Reorder the terms:
(140 + -135x + 56x + 25x2 + -54x2 + 10x3) = 0

Combine like terms: -135x + 56x = -79x
(140 + -79x + 25x2 + -54x2 + 10x3) = 0

Combine like terms: 25x2 + -54x2 = -29x2
(140 + -79x + -29x2 + 10x3) = 0

Solving
140 + -79x + -29x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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